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对于能效测试, 可以参见欧洲Directive2009/125/EC,具体如下。8 M4 j( w! l* M6 |7 P( i5 V W
Test procedure:
W( G# j$ H1 L+ t3 p1) Measure the steady standby power consumption (for adaptor without any load) P1= W while the available supply voltage is just 230V after 30 minutes. (Limit: < 0.3W); H3 M: W" v7 H* x8 n! m
2) Connecting the outlet of the adaptor with an adjustable resistor then plugging the AC plug of adaptor into the outlet of digit power meter, adjust the resistor to make sure the output current to be rated current monitoring from a ampere meter /multimeter in series, record the steady power on the power meter PI= W and the DC output voltage Uo= V measuring from a voltmeter/multimeter in parallel while the available supply voltage is just 230V, thus the active efficiency at maximum output level η1=( I x Uo) / PI = ;
7 l/ M" ^4 W/ O0 { Z3) Repeat above steps but adjust the resistor to make sure the output current to be4 g( S+ l8 q) b+ e3 ~( A& l/ n
75% rated output current, record the steady power PI = W and the DC output voltage Uo= V the active efficiency at middle output levelη2= (I x Uo) / PI = ;7 ?" w% Y! v* C( I7 d1 T4 V8 Y+ k8 r
4) Repeat above steps but adjust the resistor to make sure the output current to be7 u5 m: n% }. j B. U0 O* M
50% rated current, record the steady power PI = W and the DC output voltage Uo= V the active efficiency at middle output level η3= (I x Uo) / PI = ;
+ W: y2 E. {+ ^5) Repeat above steps but adjust the resistor to make sure the output current to be
, m- t6 k3 c8 j1 |9 E, J- Q8 |3 v25% DC rating current, record the steady power PI= W and the DC output voltage Uo= V the active efficiency at middle output levelη4= (I x Uo) / PI = ;
3 l$ x* R+ B4 Z8 HAverage efficiencyη=(η1+η2+η3+η4)/4 = ;
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