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2 W! q$ S* `! r; L
求解：标准中有说电量的计算是通过2000 Ω电阻，测出电压/时间曲线，求出电路二端的放电电量。好久没用高数了，对于此电压/时间曲线，如何计算？积分公式是怎样的？
3 c% M" n. o, {6 @. D) j" y( e1 i4 E: k. t9 D3 X' w \
If protective impedance is used, the current between the part and the supply source shall
8 ]5 i. Z; |0 D9 ]1 k, J+ `) znot exceed 2 mA for d.c., its peak value shall not exceed 0,7 mA for a.c. and; k* i1 Y5 q3 e
– for voltages having a peak value over 42,4 V up to and including 450 V, the capacitance5 z3 x/ v* B2 O* Q3 W
shall not exceed 0,1 μF;
; b7 } {. C4 I7 ^+ k% J– for voltages having a peak value over 450 V up to and including 15 kV, the discharge shall
) Z; s5 |. d2 n( Z% b3 Mnot exceed 45 μC;
8 o5 ?9 ~$ O2 p! A– for voltages having a peak value over 15 kV, the energy in the discharge shall not exceed- e% F/ W, |. C0 d- H
350 mJ.% w1 h" p+ w9 K. ~' m
Compliance is checked by measurement, the appliance being supplied at rated voltage.
; P7 @, K- a' i4 b! H0 QVoltages and currents are measured between the relevant parts and each pole of the supply
! N8 v5 Y) g. ^. _source. Discharges are measured immediately after the interruption of the supply. The- }( ?8 x( Q: l. z! W
quantity of electricity and energy in the discharge is measured using a resistor having a
- N5 R. M, V9 O, S5 \" _: tnominal non-inductive resistance of 2 000 Ω .2 X' R2 Q& R* e; j; V3 x
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发表于 2016-8-15 16:43
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