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我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.
; X% v+ e5 b* \问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:7 C: y4 q% l5 h: _; C9 \5 w
) k, Z5 G8 g0 c) P第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1' b0 [7 S4 C/ E- ~0 ^! B
20.101.1 Lawn trimmers2 L. N7 y* u: Z
Lawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown
: b2 T2 E: k/ H3 w* pin Figure 101.4 |5 S4 T. f' j; a7 i& U5 ?$ f
The radius X of the guard shall not be smaller than the major swept radius of the cutting
& D1 V! I! S4 N/ d! rhead and the guard shall extend beyond the plane of the cutting element by at least 3 mm
* |: K# x* w: A. X+ |6 E9 ofor walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall( E5 p' Q& n1 q, [7 J2 o! u4 n+ L0 ~3 ]
extend at least 45° from the axis of the handle on the side where the cutting element is
; {: c+ B7 V0 Y" H+ Nmoving away from the operator and at least 90° from the axis of the handle on the side where9 m3 [0 j$ I% P' w. Z
the cutting element is moving towards the operator. The vertices of these angles lie on the8 v% j0 ?& Y; C$ a/ O, M
axis of the cutting head spindle./ y9 j' C6 _: c1 y0 U4 I
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
% w- e5 y) u7 i* G5 O+ m+ Qshall be marked on the lawn trimmer. T+ S! w3 X; _( D
Compliance is checked by inspection and measurement.
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2 i9 k& v/ o' E9 a! W第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103! Y" q/ w+ f2 w; `6 i+ k$ ]2 B. G
22.103 A cutting element shall have a kinetic energy of not more than 10 J.1 Y) H0 k* N9 \7 M0 ]
Compliance is checked by inspection, measurement and test. Polyamide cutting elements2 z# l, [) q/ [7 Z7 w
are stored for at least seven days in a humidity cabinet under the same conditions as those
; N* P! H; T7 ~) f9 o( j& vrequired for the test of 15.3 before carrying out the test and measurement.
2 b' C) b) R1 t5 B' ?( ?" WFor the purposes of this standard, the kinetic energy shall be determined by means of the- @% m0 @( `, V9 z1 T
following formula:
. u: w: {, O v& A8 A9 N0 d$ Gkinetic energy = ½ mv2 (J)3 K% V% b ?, Y9 G( P4 V) c2 ]
where5 o# G3 Y9 A }9 W. D0 H
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);
& k; x$ F8 S3 F! |: Bv is the maximum attainable velocity of point Z which is half-way along the length L of the, d5 r% a1 F& J! i- c: ]- y
cutting element, in metres per second.) K* j$ b7 }; C( p% M" U
Therefore: v = 0,1047 n ( r– (L/2))
. E0 \8 V' ^: X' I9 o5 X6 @& }; ewhere
( `' G( p. l$ y5 n: F9 sn is the maximum rotational speed with a full length of line or a new cutter fitted, in
1 |! \- [: d7 i6 W% Xrevolutions per minute;
( z5 h! P. _( p3 `% d: vr is the distance from the axis of rotation of the cutting head to the outer tip of the cutting1 B( Z5 L+ P% W U6 h
means, in metres;0 q6 m: S8 |1 B# }3 n
L is the measured length of the cutting element, in metres.( x g' i0 s1 e+ B# M
6 z# s) v: m0 C' p: a; O g F4 b
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