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|  DSH 387
) l+ |' s3 ]2 m
1 o2 H- R: c- p2 ` | Hazardous Voltage
, L$ L0 P Y1 v | 1.2.8.3 / 12.8.4- i7 C; ~2 r, L) w
| 60950(ed.2) & 60950(ed.3)
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8 D$ a- e! r% W3 Z0 I ^% L: {7 R+ OStandard:5 g E+ b8 }7 B4 S7 F
IEC60950, 2nd (3rd) Edition2 z- U* C/ d" h% n
Sub clause:
, B: ^) c- x, T2 f {" W1.2.8.3(1.2.8.4)
4 r7 ^& [3 F' F) M6 ~3 e aSheet n. 387. @1 T! U8 Y% c3 _+ x8 m& v
Page 1 (1); m6 b6 G, R) {: g( L# H$ U
Subject:' u" b* g% I/ ^0 f6 H. y
Hazardous Voltage& v( T& o1 H" v5 g" ]9 F& h
Key words:1 O9 ~. V1 n; r/ Y2 T; S' B5 T, A* j
-Hazardous Voltage
; n; O" t3 C- t) H9 ADecision confirmed4 R) t- F* ~9 H7 J) N" |/ L
at CTL 38th meeting
0 {0 O" c0 b) `4 _$ E S) Z0 \9 v% VQuestion:
1 ], S' k! b- O( K0 h) `Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance$ \: w6 A- k1 k) ~. e; L
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?
1 ?+ l! i% }2 y6 A2 iCondition: The circuit that generates this voltage is not a limited current circuit.
1 {; P8 b* d/ N, b7 K! B, t: [9 {Decision:
# I$ G( x* m3 q! gThis voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3# w4 m( S$ p2 Y6 ^$ n
& ~1 p/ Q# K$ M( o& D% }
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发表于 2012-11-6 17:16
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