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& n1 L0 @. m1 M9 wDSH 534
; e8 x) o( Q) U) B% O6 ~+ Y- T d | Figure 21, presence of resistor of 45 kO
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| 60601-1(ed.2);am1;am2
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4 i/ G4 m% ]' n; Y \6 VStandard(s)- (year and edition):0 H$ o( i& `3 A) y8 q/ i
IEC 60601-1:1988 Ed.2/ u$ u) F- P0 r1 @9 ?; ?1 G# }+ w
Am1+Am23 I* }2 i5 B; g4 s
Sub clause(s):
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: _0 |0 R, \" eSheet n°: 534
0 N$ J3 s z" Q) ]2 dSubject:
" q6 _0 W0 O: g$ v4 HFigure 21, presence of resistor
$ R# o+ B% \+ U' }& k9 d9 N) Q6 n6 S+ fof 45 kO
$ q7 i$ j- k( y# D' NKey words: Decision taken at the 40th" c) v# l- B* U y4 T
meeting 2003
" q# t5 t0 b0 n& y p; XQuestion:8 v1 n6 \, H# P1 C
Should the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?
" W) j# M. f. LDecision:
2 E- r& M! c0 e6 dFor the 1st edition, use the method of 2nd edition (use any resistance).
) n" [0 R: i, rFor 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses., f* U8 q; e+ y3 Z& q
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