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|  DSH 3874 t. H& Z2 L$ H4 R2 X
8 w. A0 ?" j4 m3 w$ u, G | Hazardous Voltage
0 @# d* Q8 N8 {0 \ | 1.2.8.3 / 12.8.4
4 v9 A0 E$ r( s | 60950(ed.2) & 60950(ed.3)
1 k* i R* a6 q4 C |
$ y7 B2 ]9 U2 V5 {) a: QStandard:
2 D- m! L0 g0 A: e# o! `7 p' U6 N5 qIEC60950, 2nd (3rd) Edition3 s( ], z0 P/ o: `( F; c
Sub clause:! q: Q0 b& }0 j- X1 N
1.2.8.3(1.2.8.4)! M/ O' ~: J8 B' i- I$ L
Sheet n. 387
. {$ O+ e4 E* b% Q, R- N" cPage 1 (1)" d% z6 }& C6 U0 K$ z* \# s* ^8 m# F
Subject:! G( s5 | n# t
Hazardous Voltage. Y4 q$ `2 u! H$ O
Key words:; u: \1 B7 O& `" H0 M# P- j( K, j
-Hazardous Voltage
. p( o3 V8 Q* F* u% N9 IDecision confirmed. M; h3 |* j. l5 \
at CTL 38th meeting
, J7 b- g/ I' O& O0 a; |# ^Question:
/ }% Z' E1 J M8 n) @9 DWhich of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance, D* P1 |5 W# Q b' E" p. o* z7 @
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?& l! c( Z( O+ ~+ o. V0 g* [
Condition: The circuit that generates this voltage is not a limited current circuit.
# ]' Q3 s2 m, j& ^( IDecision:
( M' p& Y/ ]* z5 N7 T3 ]( XThis voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3( y1 @9 U6 m: |8 S5 h$ R2 b, W
, ~, `8 @4 u, q
! v2 w& s& \" m3 x( W |
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发表于 2012-11-6 17:16
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