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| Figure 21, presence of resistor of 45 kO
. i$ n: @! q" R | 197 e$ y! W& S: k1 q# s
| 60601-1(ed.2);am1;am2- D& c0 |6 m. {1 e2 c+ [
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0 F2 x) J; S! Z, [6 P4 MStandard(s)- (year and edition):
) ~$ s9 M, A) c/ C- D: xIEC 60601-1:1988 Ed.24 ?* t* q! ^" c/ x- J7 L' d; [. v
Am1+Am2
9 [+ J; ^& m- |% H/ @3 i6 hSub clause(s):
: |! ^4 T. d& P* _& F19! d% l; V2 t3 y6 r- n1 d
Sheet n°: 534
8 C' u- u% I3 t7 m* ]8 nSubject:
* L& j2 N7 U& U6 lFigure 21, presence of resistor. U5 y8 S+ X% c2 [3 v
of 45 kO
* L8 }5 w7 a% u3 Y7 k3 Y9 g6 ^Key words: Decision taken at the 40th
! m7 D+ o& u% E6 n' w; W, Emeeting 20039 X3 g$ ?! X4 I3 Z
Question:/ ?; {8 g& z9 _; I
Should the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?
3 p* R6 B* d$ M) X- [( f" aDecision:0 Z' m/ W9 M2 u' z5 ]* N0 Q
For the 1st edition, use the method of 2nd edition (use any resistance).2 x6 r. Z+ D( M Q- }$ }
For 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.! m+ F8 U; o6 ~& [
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发表于 2012-9-19 15:49
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