|
我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.; i0 T: t% f8 K1 e
问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:* c7 c9 K: v$ X6 b$ W( j) V) w. h7 N+ c
2 p" @3 [# X( ]+ }第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1, ~) C/ ]" D! f: O
20.101.1 Lawn trimmers
3 I! c; E8 |/ m7 e1 W6 ?' pLawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown! i7 b4 H, w$ |! ? h) h! j3 B) u
in Figure 101.
+ t) [) k& G o" g* y# XThe radius X of the guard shall not be smaller than the major swept radius of the cutting) i7 \+ ?; B* k7 u* w7 r5 x
head and the guard shall extend beyond the plane of the cutting element by at least 3 mm
+ d$ P# M) E4 L! Dfor walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall
n: w$ b& E* _ I9 e: Uextend at least 45° from the axis of the handle on the side where the cutting element is8 r! I& B" D4 b+ G; b5 i6 f4 R
moving away from the operator and at least 90° from the axis of the handle on the side where
q: Z- R6 _! [/ F: W" {2 e/ Lthe cutting element is moving towards the operator. The vertices of these angles lie on the
. E! B( [8 n S" ]7 V* D0 Waxis of the cutting head spindle.9 u" o2 m6 L, ?4 }. k1 y- ?
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
- |, g3 \0 ]; c* w) I) b* q0 Qshall be marked on the lawn trimmer.
$ `$ O( [# f% t1 [# iCompliance is checked by inspection and measurement.7 P d* l: F7 Q; V- h
" i. h+ A: A+ f0 }第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103$ v3 J7 E) R' R9 Y0 M, t
22.103 A cutting element shall have a kinetic energy of not more than 10 J.
0 g* U- w/ E2 M- F- m4 ^' HCompliance is checked by inspection, measurement and test. Polyamide cutting elements. C5 }+ B6 M. J+ i' b8 x1 k$ s
are stored for at least seven days in a humidity cabinet under the same conditions as those( R0 ]- [- v, C- R
required for the test of 15.3 before carrying out the test and measurement., k- c. e4 o# d8 m
For the purposes of this standard, the kinetic energy shall be determined by means of the
# b c5 z4 g/ Z3 i) `3 H- h( mfollowing formula:
2 ?: H3 k' G0 B6 [9 ^kinetic energy = ½ mv2 (J)$ h3 z/ V$ i4 f% U7 F
where& V6 {6 p' V |3 ^: Y* d
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);
: I0 z& ?- N) v9 d! `v is the maximum attainable velocity of point Z which is half-way along the length L of the
( ^& \9 K# \# n8 G! ucutting element, in metres per second.. K) x C+ B! r/ A5 l# d6 b: {) t
Therefore: v = 0,1047 n ( r– (L/2))
3 ~! n( o7 E1 d) B" X2 [where8 m; r6 z K- s6 Q D
n is the maximum rotational speed with a full length of line or a new cutter fitted, in
/ R1 v2 A, @$ f7 D' I: ?/ Vrevolutions per minute;3 S5 r. i5 ] j& U3 s
r is the distance from the axis of rotation of the cutting head to the outer tip of the cutting
4 P4 @1 i( _0 L% Tmeans, in metres;6 U% m& q6 s) d6 Q4 _
L is the measured length of the cutting element, in metres.# {2 Y6 m, L* g) p/ L1 X, }
5 N5 C0 X( P) [/ K
0 B( h0 W! @/ Y1 F
|
|