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' G" T! w: _, w8 b4 M+ C3 J& A
Standard:4 ^1 z" w) _! g" M; O% c }
IEC60950, 2nd (3rd) Edition6 y7 a3 B: E9 f; C" F4 v
Sub clause:" T/ H( h X$ G* G. U
1.2.8.3(1.2.8.4)
7 S2 n7 v' o: t8 g* z6 PSheet n. 387* S$ s. |8 W9 D# z
Page 1 (1) J# u( P5 O" L/ h) T4 w+ n5 F
Subject:
9 F; G* n2 ~# t, b$ U# qHazardous Voltage* v+ e) T; O% y; {, C% j
Key words:% Y! E G. `: g# W( C+ s
-Hazardous Voltage4 e0 j' g; C0 j: n9 W
Decision confirmed
# S1 u$ h5 A6 _( \ g: oat CTL 38th meeting9 m% U: }' e; N+ j3 s; \" u
Question:
% d! b' ~5 m4 S" V+ ?$ WWhich of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance1 r8 T- H7 [/ F- k: y3 E5 S
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?
- A$ i$ _' n- ?8 ^% H6 f8 LCondition: The circuit that generates this voltage is not a limited current circuit.6 _ j+ ^* B) a5 A% o
Decision:" K2 x: j8 {+ m0 Z* J* K4 I
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3
6 t( D, w/ |8 g$ `0 [3 @4 b7 t4 A2 A" e" r
% Q- t! o# p$ K# W# u" e
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发表于 2012-11-6 17:16
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