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| Figure 21, presence of resistor of 45 kO$ ~' ]6 l$ K. B$ N5 `
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! {0 x1 C& p, Y/ B( D | 60601-1(ed.2);am1;am2
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1 u) g- [! S) _: r$ X0 |: `' R0 XStandard(s)- (year and edition):
5 A; _3 D2 h$ \. n5 q, R% M0 u QIEC 60601-1:1988 Ed.2
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Sub clause(s):
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Sheet n°: 5340 J' l+ c) O6 C* i& u) i( |% O4 I
Subject:
2 Z/ a3 ~' e, n2 i0 Q7 NFigure 21, presence of resistor
6 v5 B1 P) w6 j4 g3 t! b, i$ vof 45 kO
0 Y6 o; A/ C! |& P! ^$ T+ V4 B2 ?Key words: Decision taken at the 40th
8 {& }7 n7 z1 S! q3 ~* Nmeeting 2003
; X' i& ^0 B5 x6 d2 |' @7 iQuestion:
0 N$ P1 T6 h9 U: ^, fShould the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?- ^' s0 {, M( ?% {, b X
Decision:
- L) P2 ^" e, e9 q6 h; S+ [For the 1st edition, use the method of 2nd edition (use any resistance).
) q6 ^& Y9 ~( qFor 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.
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