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引用第10楼franco于2009-05-07 20:39发表的 :
3 \- c2 k7 h$ r' v' D# q/ wThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
) h v3 h6 A5 z4 `+ |either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per $ V _% W+ ]% [0 E' R: ?; b5 }* Y
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
0 _- }& @3 N/ Y! T' j8 K; |3 Hsample is turned through 90° about the centre line of the cord guard. 2 I; N/ p0 d* U: O# F1 S8 ?
1 d9 W5 Z. R6 Q: [6 \ ^) T( s: ?....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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0 T1 V7 Y4 G2 V: J% v/ y- k翻译成中文的主要意思就是:
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on
3 o5 q T2 S1 @3 X' Seither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per , z8 y* G& N2 ?) J6 S
min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。* w) o- X0 S1 m7 q- T& a
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这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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+ [+ j; {" ~+ e. j p& j7 CAfter 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。; G4 K: Z; U. J( I7 w" N! U
( y. w- S* e; W' n5 _+ C这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。2 h, Q# n2 D+ X& C( { @! ^
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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7 @6 o) ^# ?) ^这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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A flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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