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引用第11楼zihui于2007-07-24 20:23发表的 :
. e! @4 ?' [+ D60950中的Steady force test,无论是10N,30N,250N,的力,都是用TEST FINGER来施加力吗?应该是有专门的推力计吧,这样才能读数啊?! F% W+ K* Y. m2 v2 h
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还有我怎么判断该实行这样的力?能否举个例子,谢谢大家 6 g8 y$ L8 |! n+ Y( R8 K
4.2.1 General(一般要求)
8 a7 [0 N3 u! n$ m外壳应具有足的机械强度。若外壳提供了足够的机械防护,对于为满足4.6.2而提供的内4 m, i z0 H( D5 j
部挡板、罩或类似物,则不要求进行机械强度实验。对于所有的设备要求通过4.2.2,4.2.3, * d; R0 P) q! z6 v
4.2.4,4.2.5的测试,对于手持设备还要求通过4.2.6的跌落实验。 0 E' M! V6 U: L: c: P6 {% E- P
4.2.2 Steady force test , 10N(固定力测试,10牛顿)" J+ |8 S2 M3 B& }$ x% v
Components and parts, other than parts serving as an ENCLOSURE (see 4.2.3 and 4.2.4),are
, P0 z; j/ c3 p& o* xsubjected to a steady force of 10N+/-1N。元器件在承受10N的外加力时,不能影响到安全。
9 f5 o$ a7 M6 o 4.2.3 Steady force test , 30N(固定力测试,30牛顿)! ~) d! b& I- H U# `9 A# X
Parts of an ENCLOSURE located in an OPERATOR ACCESS AREA, which are protected by a + d+ G7 i9 x( p4 {; D) Q( Y
cover or door meeting the requirements of 4.2.4, are subjected to a steady of 30N+/-3N for a
. ^5 Y+ k1 U5 \! P+ G6 t; [8 u" Rperiod of 5s,applied by means of a straight unjointed version of the test finger, of figure 2A(see 2.1.1.1), to the part on or within the equipment.安装在操作人员接触区内的并由满足4.2.4要& _9 i2 c1 y' _6 _; T$ h2 E+ t
求的罩或门来保护的外壳零部件应承受30N+/-3N的恒定作用力持续5s。
& X/ x6 u( ?* @* z+ @ 4.2.4 Steady force test , 250N(固定力测试,250牛顿)% B3 U% z, p! u4 {% M8 @/ F8 ]
外部防护罩应承受250N+/-10N的恒定力持续5s,该作用力通过能在直径300mm圆形平面上进行接触的适用的实验工具,施加到固定在设备上的防护外壳上。 |
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