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| DSH 525" ?) j+ U1 f4 t
, o7 G6 Y4 q+ v* X
| Applied force for internal parts
6 n- T1 P9 o& a6 B5 z" C | 13.2
1 r3 {. Y; O. C. u6 J | 60065(ed.6)
; H7 O$ W* a5 N L4 P. W, Z |
1 Q9 K% d, g+ m. e0 Z5 j$ f3 bStandard:
% x! x! V5 l1 U' oIEC60065 6ed.3 r5 }4 ~, ?3 H2 X
Sub clause: f A$ y0 f( I+ w3 N
13.2- o) \& M8 d5 ?3 D6 d
Sheet No.
8 v. d4 V( \/ L: ^4 H4 t" R; U$ z525
D k4 B" d1 C. }- k% a+ MSubject
A! j) F, k7 o* A( W: }Applied force for internal parts9 W% ?- T3 x# l f) j0 X# _
Key words:7 l' I7 b. Q' ^- G" ~7 T" n
force for internal parts3 q' w" X3 O, `: j* Z
Decision taken at the
& \# p# `4 |4 h/ }5 N40th meeting 2003) q; F# M- a. y# N- x# O
Question: ?( b$ w% ~- _* G8 p
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied# T U4 f5 u" j/ @2 |8 h9 i
simultaneously while taking measurement of clearance. However, it is not specified that forces are
) S: [6 T9 }' q" s! }; S/ [; `! t- Iapplied to internal parts while taking measurements between two internal parts, ex. primary circuit8 E( a5 i% b$ r' f( m
component and secondary circuit component.
9 j( u0 \$ z; O) x+ D i; fWhich is the appropriate method to measure clearance between two internal parts ?) s+ b- I+ `5 Q
a) 2N forces are applied to the both parts simultaneously.2 W$ D7 V9 b" T7 ?
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.! f) \ b. P8 d; Q- A
c) Other opinion
$ A0 U* l+ N+ i3 n g7 {Decision:
7 Z' b* T: C& ^First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other4 g4 \- c9 m; K: G
part.1 T" |& C! N* c
( b( T* C8 c/ i, H+ B
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