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各位好，现在有一款 电池充电器做GS 现在不讨论其他机构的看法，因为就莱茵有以下要求：
- o: d& p. _7 o# \1 K% x莱茵依据：
% Z: R7 q5 d' `1 q22.26 Replacement:6 F7 N( U: H% g, z* E P( M; N& f
The output circuit shall be supplied through a safety isolating transformer and shall not be; u" f; v! w( b* [& l
connected to accessible metal parts or an earthing terminal. The insulation between parts) |& i) A; ?( K9 S, e
operating at safety extra-low voltage and live parts shall comply with the requirements for3 G1 x- Q& q+ V$ P' Y
double insulation or reinforced insulation.
& P% ^' \; p) e8 w" hCompliance is checked by inspection and by the tests specified for double insulation or
- O; f# x+ }( ~6 l$ treinforced insulation.1 e2 M& F& P- q- ~% d0 U" {
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然后参见 60335-1 safety isolating transformer 定义： a" c3 A# J4 Z! `) |5 B
3.4.3
1 y* P- m0 M' f5 Y( @& e3 {safety isolating transformer
3 n8 x( P' v0 p" K o0 Jtransformer, the input winding of which is electrically separated from the output winding by an/ S$ d, I8 l; f
insulation at least equivalent to double insulation or reinforced insulation, that is intended& }' m& b) ~6 \, n7 G3 k
to supply an appliance or circuit at safety extra-low voltage# y' y+ N+ h! Q M- I# D: K, m: H% y
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! e" L# E2 s6 k3 r% Q* h3 {现在抛出问题 ;我的充电器输出端子插入电池座是不可触摸的，输出是 29.4V 2A，正常异常测试输出都小于42.4V，
$ E9 j- J5 @! N& D1 _4 m) w空载保护没有输出电压
9 j0 P( S1 M5 x9 ^2 i但莱茵按照 safety isolating transformer的定义 一定要求我变压器输出端要小于42V，才能做60335-2-29的GS，我个人
" ^- C' o1 L4 O5 [6 k. t觉得很没道理，这个地方的safety isolating transformer 不能这么理解，还请各位发表下看法，以便我能找到更好的依据,多谢！！！！！
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发表于 2014-8-27 16:00
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发表于 2014-8-27 17:39
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