DSH 525 Applied force for internal parts

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DSH 525 % K& N) P; L4 ~3 r$ f0 J / O7 P! u! e+ Z* L1 L/ s9 w' i- C

Applied force for internal parts 7 l  t5 q1 H& u: l6 A5 D6 t

13.2 2 o( o, M1 q, Q4 z) `) S4 k( R

60065(ed.6) ' y: k6 a! o" v+ F4 G7 j7 W

2 ]. @  f; f" O( G! X' dStandard:
IEC60065 6ed.
" U8 Q. |0 J$ N; z; n3 e; iSub clause:
3 W+ u& s4 b9 f5 @/ ]+ [& T, |13.2
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525
* `; o2 {- z" o, ASubject
Applied force for internal parts
Key words:
. o" Y7 d! t, kforce for internal parts
Decision taken at the
* Z* c, {+ N, `: Q) j! q40th meeting 2003
) |$ k1 D* s1 g$ [0 w8 }  gQuestion:
1 f+ w( r% _9 }3 B# K( R$ _In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
2 @% f# C! q$ U1 K0 C6 {7 X& [, g, Psimultaneously while taking measurement of clearance. However, it is not specified that forces are
9 u" |5 [- i. ~1 Rapplied to internal parts while taking measurements between two internal parts, ex. primary circuit
$ T; k9 f, t/ h9 V' x  U& t0 ?component and secondary circuit component.
! c' X8 G1 f: Z1 b3 a* s% j: fWhich is the appropriate method to measure clearance between two internal parts ?
0 ^" w6 M/ e/ ma) 2N forces are applied to the both parts simultaneously.
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.
c) Other opinion
Decision:
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
8 G) N( [  }; y' L! Q: |+ ^4 L! c5 o  Cpart.

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