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|  DSH 3875 T5 x3 n/ M# p% Z( G4 o
+ W- C# q1 J7 x1 d, { | Hazardous Voltage1 @: [; m% B: V7 |1 l/ l
| 1.2.8.3 / 12.8.45 X6 H5 }$ s0 t( [$ h/ J: i( t
| 60950(ed.2) & 60950(ed.3), Z9 @" m |0 x( P' E
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8 C8 x, q, A( q9 d9 ^
Standard:- i# J, ^1 k4 h# z8 e
IEC60950, 2nd (3rd) Edition3 h% M. T* L- [
Sub clause:) R0 D2 o) s2 D, H0 C
1.2.8.3(1.2.8.4)
' p3 M( [$ G& ^( [3 D) e! \- GSheet n. 3872 y7 H4 u u$ j5 l; X7 p
Page 1 (1)
$ \1 N V# [+ A1 [Subject:' M& V: Q* _# V; h& P0 p+ O1 _8 a
Hazardous Voltage
0 r$ X7 o. ^, O# c' j- S5 t. |Key words:
% g0 m7 V6 P! [9 ] Q-Hazardous Voltage) k1 U7 p4 u7 v; [- ]
Decision confirmed
% d" G5 K. B" |8 Gat CTL 38th meeting
7 t- S! {) H. _0 vQuestion:6 \8 T- v" u2 l( o1 v
Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance
" T" S+ ?& K+ e; N. u! `criteria, in order to determine whether the voltage shown in the graph is hazardous or not?
. Q* \' `: {, y/ rCondition: The circuit that generates this voltage is not a limited current circuit.
4 d* \+ V* h$ S! V# TDecision:5 a0 H/ ?. m0 Q; v- Z
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3: i+ h3 W6 |. }8 Y7 `* d7 w
( @$ a" t5 v4 R' [% s3 i
/ ~: s9 \& j5 x0 L: u
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发表于 2012-11-6 17:16
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