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| DSH 525
4 P# L6 ^: @9 b3 N0 `7 L l7 J3 X, {5 @, ?
| Applied force for internal parts x5 e) @& n& s9 ]1 W: Z- l; Q7 b
| 13.25 f0 @$ ^! ]: O9 K
| 60065(ed.6)2 D7 b9 U) Y/ n$ `6 r) z, I
|
1 l1 x' M- d9 }5 LStandard:2 F2 ~5 m$ I: v C$ @
IEC60065 6ed.. D7 l/ s: E: k1 @( Z
Sub clause:# B* a- q. p2 w; q" l
13.25 f$ M# H) Y3 F0 v8 e/ c/ _- x% E$ c, q
Sheet No.* H; B# c1 E4 I
525! ~8 X9 Z9 E# b- a. b5 r# V' r
Subject
7 u ~) s8 P2 A2 ~2 _Applied force for internal parts
0 |6 T( r: j i$ HKey words:
* J& Q* u3 b [3 Fforce for internal parts
4 ~( e$ c, c* }+ d0 t+ qDecision taken at the
/ e/ B4 G4 E Q40th meeting 2003
$ T/ @$ |* X4 U7 W2 @Question:1 n8 V' P, _- Y+ ?1 w" ^8 a- X
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied8 v& O3 n$ [5 k7 a9 n3 L+ t3 p6 v
simultaneously while taking measurement of clearance. However, it is not specified that forces are
+ m4 `! l+ s, H8 eapplied to internal parts while taking measurements between two internal parts, ex. primary circuit4 {. X- N; o& m* X3 d0 P1 G+ p
component and secondary circuit component.
$ _0 A6 j" S5 n* j: f& ~1 Y' R, I" P6 RWhich is the appropriate method to measure clearance between two internal parts ?
5 q; h( @6 h/ C4 Ba) 2N forces are applied to the both parts simultaneously.7 R, ]; i& Y+ R
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.7 W! e5 @ l" }9 P
c) Other opinion
: W" ~3 c+ B; e2 I) s, ZDecision:
3 e' I* g. p; L _# OFirst, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
$ u) G8 t' r2 a% G0 H$ l+ c/ u# p# J6 Mpart.4 F, ?" j0 O* l4 E
) [8 A. p/ t/ q3 o4 q2 _7 R% L
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