标题: 电动打草机线头飞溅伤脚问题 [打印本页] 作者: terrywong 时间: 2014-3-15 18:44 标题: 电动打草机线头飞溅伤脚问题 我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.* r; I% ]$ U0 G. |' ?- }2 i0 f' D) O
问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:5 E7 A! z7 U% ]& v, Z: ] K2 b
, w( k7 ?; Q% R第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1 ; G' d# v7 `; _7 H' @20.101.1 Lawn trimmers0 ]' J, m) n5 A! m l
Lawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown+ n% q* C1 f" K7 a f
in Figure 101. ) Q: Y1 \4 V5 ?8 K6 `* qThe radius X of the guard shall not be smaller than the major swept radius of the cutting. @# Z8 t4 m: V7 d0 b: J
head and the guard shall extend beyond the plane of the cutting element by at least 3 mm! K$ a2 ]$ e0 s4 U/ s4 [" [
for walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall 0 Z3 n; d( h* _& `7 X8 O6 Bextend at least 45° from the axis of the handle on the side where the cutting element is , G; N- M1 I0 R+ C- o2 Cmoving away from the operator and at least 90° from the axis of the handle on the side where- v" P) G( t6 o, d
the cutting element is moving towards the operator. The vertices of these angles lie on the& ^9 ~/ X1 a, ^% `, q: _
axis of the cutting head spindle.& q7 V* z$ Z) i% S: s. @
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)$ ~9 x* C" I9 Q9 d6 ^ F4 w+ J
shall be marked on the lawn trimmer.( d3 Z% b$ J: I4 F
Compliance is checked by inspection and measurement. : Z3 b( A$ m+ r( y 3 @& ]) ?9 s6 F( {1 D: h% r第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103 j/ [. {" d) ^0 `
22.103 A cutting element shall have a kinetic energy of not more than 10 J. % b5 t8 Z! ^- Z; K- \" Q2 }Compliance is checked by inspection, measurement and test. Polyamide cutting elements& r, b+ ?1 j7 G- R1 X* t9 c# K$ j
are stored for at least seven days in a humidity cabinet under the same conditions as those% l0 M# q, p3 v, ^2 g- E4 Y, H
required for the test of 15.3 before carrying out the test and measurement.# D7 P/ w2 ~/ h3 x3 Q7 }
For the purposes of this standard, the kinetic energy shall be determined by means of the8 ]) n& i# X) ?6 {% Q1 B
following formula: & W$ k) y7 _0 Rkinetic energy = ½ mv2 (J) 4 _( f$ i" a3 S: V$ V9 ^3 Ywhere: U3 X6 e: F, M4 n- Y$ h
m is the mass of the length L of the cutting element, in kilograms (see Figure 105); 7 G2 [$ ]: J2 A4 Q. Ev is the maximum attainable velocity of point Z which is half-way along the length L of the( L6 }- t4 |( J ~5 w9 G
cutting element, in metres per second. * h5 C' ~ Z4 t1 ?/ m; JTherefore: v = 0,1047 n ( r– (L/2)) 2 [7 f% F/ a. s. U! x Mwhere 4 [2 u' O- a/ o9 Cn is the maximum rotational speed with a full length of line or a new cutter fitted, in . O7 [2 [; g% J f/ c% e0 frevolutions per minute; ) y5 o' }0 n& ^, q- R; hr is the distance from the axis of rotation of the cutting head to the outer tip of the cutting . S5 Z9 Y' `, i- _' vmeans, in metres;% h& R0 T" K( d, R8 [
L is the measured length of the cutting element, in metres. 9 @/ j3 O9 F" I5 }+ c' o5 s. m2 h0 r, G