标题: 8.1.4的测试 [打印本页] 作者: 小猫咪 时间: 2014-2-7 11:05 标题: 8.1.4的测试 If protective impedance is used, the current between the part and the supply source shall0 d9 ?1 B1 K/ O! M
not exceed 2 mA for d.c., its peak value shall not exceed 0,7 mA for a.c. and' S2 [- D* W/ q- x# P( N1 c
– for voltages having a peak value over 42,4 V up to and including 450 V, the capacitance6 Y* ]! ^! I8 d% q ~
shall not exceed 0,1 μF;! s1 c6 L+ `+ W# _. w6 m7 u$ n
– for voltages having a peak value over 450 V up to and including 15 kV, the discharge shall8 x, O. h# ^+ y. R
not exceed 45 μC;6 l% b( x/ D' i+ H
– for voltages having a peak value over 15 kV, the energy in the discharge shall not exceed $ ?# N4 J) ]* b# C8 x! {350 mJ." b: x" m7 A$ U, p
Compliance is checked by measurement, the appliance being supplied at rated voltage. # \, b( _( R9 Q8 s 这个放电量怎么测量咧?有没有高人啊??9 _; H4 n6 W. i 作者: 山炮 时间: 2014-2-9 14:45
能算则算,一边放电一边补充能量就无法算,只能用专用设备测量。作者: craigyu 时间: 2014-2-10 10:35 本帖最后由 craigyu 于 2014-2-10 10:36 编辑 2 `3 Z# g. ^( D6 F0 _; `7 t$ i) i O' h7 ]3 b+ f* S4 V
参考60065的9.1.1.1来测的作者: lotte_528 时间: 2014-2-13 15:03
用示波器的积分功能测量作者: 小猫咪 时间: 2014-2-13 15:21