Applied force for internal parts ) [+ P/ Y, G- [# W( ?) L( H; O8 j, c
13.2 1 R9 P9 y3 X# l0 e
60065(ed.6)- t0 Q1 ]9 S6 o U7 a9 ~5 [
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Standard: 6 I+ L& a' v# ~6 WIEC60065 6ed.: z! F0 u% P; L/ L/ B2 K2 O
Sub clause: ) \, }9 q; \: M' \2 J13.2* R1 k2 D7 Z* v/ y) X' ?6 a
Sheet No.) _2 f8 a/ e/ e
525& Y- c7 Z' o) p* n
Subject2 `- _5 a3 T& q4 w5 m
Applied force for internal parts 3 A" c) p# `1 [Key words: 9 G! K4 @* g* A; B( wforce for internal parts* n4 A0 W; N3 @ j+ ?. _
Decision taken at the . i0 h% |& m2 T; p: w5 h. X) ~, k$ X40th meeting 2003% Y/ K) r: q: s
Question:5 Z/ ?, x+ a6 H V6 n$ y
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied ( ?( e; T6 X' M$ m" l( m8 u% a1 m" Ksimultaneously while taking measurement of clearance. However, it is not specified that forces are5 z2 _1 ^: p8 @0 [) M( x/ [
applied to internal parts while taking measurements between two internal parts, ex. primary circuit. c; Q+ i* ^- a5 I* ~- J
component and secondary circuit component. " C& J, }9 v( I8 R2 {% F6 B4 yWhich is the appropriate method to measure clearance between two internal parts ? : r6 y* d2 C) ~a) 2N forces are applied to the both parts simultaneously./ g4 E k8 v3 \* ~& P0 M1 @
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.' O& h v# j! y3 |& z$ i
c) Other opinion 7 T; ]$ L7 v* K6 cDecision: 4 z1 m7 X y" [- X/ W- r0 qFirst, a 2N force is applied to one part and removed. Then a 2N force is applied to the other 4 F m" }; X4 Q: w6 s. H: e1 k6 A5 Rpart.! l9 o- j: B9 ?1 J) }( H/ n7 c* X S
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[attach]77295[/attach]2 b6 C9 t3 C: F* c- |" m- M
DSH 525; W- \) w0 @! |0 b! D