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标题: DSH 384 Lithium Cell Protection [打印本页]

作者: 小米    时间: 2012-11-6 17:28
标题: DSH 384 Lithium Cell Protection
DSH 384( c, V+ X" f" N

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Lithium Cell Protection
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4.3.217 {6 Y3 D8 [7 P5 H- u5 K
60950(ed.2)
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Standard: IEC60950, 2nd Clause: 4.3.21 Sheet n. P384
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/ u8 b  U! c' ]Subject: Lithium Cell Protection Key words:9 e/ l: g! l- [9 d& i; e
-Lithium Cell- S9 S3 i) W/ [8 ~  ~
-Clearances& i! r8 R+ H! B: b/ _, {
- failure mode
  o, S, b9 c  bProvisional Decision taken by ETF23 J. n0 J) a% M2 N- Y, g! f
and to be approved by CTL at its
  |1 i0 d7 M& O- j! b38th meeting, in Toronto  p5 x  A" ~7 a4 Z6 [6 E8 A
Question:
5 E! Q! c9 p; ^# yClause 4.3.21 requires that two levels of protection are required to prevent forced or reversed charge
2 z: |6 Q. P% a/ f7 d2 Nor forced discharge if this would result in a hazard. Conventionally a combination of resistor, diode
" S: ~. j6 A7 [) H7 u8 f) aor ic has been considered suitable and is for the series current path. However, a new consideration
4 f6 o7 J6 t: _% ]& z( B+ R8 b1 Ahas been raised in respect of adjacent tracks, separated by no more than operational insulation, which,
- p& T- ]' n) t0 z- K% wunder s/c conditions will bypass the protective series components and provide charging current for
% y5 B* c- h( aeither chargeable or non-rechargeable batteries. Does this mean that there is therefore a requirement6 S7 y, E# M/ x% l! j
for Reinforced separation?
1 z& D9 T/ E7 j2 H5 PIf that is the case, then the controlling factor is the clearance of 0.8mm in Table 5 (circuits not subject
1 v. O" D5 h( lto transient over voltage). This is based on the fact that creepage cannot be less than clearance and
* j$ V3 U' m! t6 z: Ycreepage can be calculated to be, for example at +5V, 0.4mm (based on rounding up 0.12mm to" ]' z+ R8 P" j# {) S2 ?5 }
0.2mm for Basic and doubling for reinforced.
* j+ `! F* l4 z4 V4 q" h/ eDecision:( A: |5 _1 g. O( g5 y# n. \2 g
Operational insulation is suitable taking into account 5.4.4 because there is no risk of electric shock.( }  Y8 h. w% B  J
(see 1.2.9.1)$ K0 E$ \" e( y4 ?# K% J
Care should be taken by determining clearance and creepage distances which column of the table has  p0 \' o6 U, s; d6 B0 b( E- l
to be used.(Transients have to be taken into account)* _1 R' E+ l# r, O% w! D
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