60950(ed.2) & 60950(ed.3) , ] O6 F* v B: R# W0 K5 f1 X
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Standard:% u6 t: S2 Z: f4 g* d% U2 b: d
IEC60950, 2nd (3rd) Edition " X$ K- o( I8 ^2 x7 F% D. }: P! O' B" YSub clause:1 s& R. |8 y- D: `
1.2.8.3(1.2.8.4)4 s8 m3 h- G, m$ L7 x5 M% f
Sheet n. 387% U! {, m: ^2 A$ `( P/ H- F
Page 1 (1)# C$ J' ^3 H, P6 b# x
Subject:8 b% B5 d8 W5 [# C- ~. X4 h# Z+ `
Hazardous Voltage ! Q6 y2 P. k6 i1 s; |Key words: d3 |8 |" m# H: c
-Hazardous Voltage# G* r" K" w) b8 Q1 J6 x
Decision confirmed ( s8 T1 i6 g! T* q9 Dat CTL 38th meeting , V, G2 ]$ K/ @! v8 `7 D* XQuestion:3 M7 r2 i3 g9 R4 T
Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance& j8 \+ O8 D4 J2 v) G
criteria, in order to determine whether the voltage shown in the graph is hazardous or not? ' M9 S# {/ A, JCondition: The circuit that generates this voltage is not a limited current circuit. 3 F7 h, H! q1 k8 G' [ P, dDecision: s! t6 u$ ~, H* [; v8 ZThis voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3, l+ z2 _/ g6 u+ d' J
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[attach]77172[/attach] . B7 {: M% I. h. U g
DSH 387; V+ v; m5 ?; q