标题: 热敏电阻NTC和PTC作用及AC/AC充电器能效测试 [打印本页] 作者: 刘阳 时间: 2012-5-22 23:02 标题: 热敏电阻NTC和PTC作用及AC/AC充电器能效测试 小弟有几个问题想请教各位大虾，希望各位能不吝赐教。# |' r! d6 |. q; s4 ]
1、关于热敏电阻NTC、PTC的区别及主要用途。 ' s( ? @& M6 v" b! I- w5 @+ P2、输入及输出均为交流的充电器的能效测试应该怎么做？3 ^/ ?( Y' U( }) \. V5 N+ w, i U$ x 作者: 刘阳 时间: 2012-5-23 22:30
求解答作者: jackyhu68 时间: 2012-5-24 08:10
NTC熱敏電阻，主要用於溫度檢測或溫度傳感；7 \5 }) Q( x& ~) d8 f: L [
PTC主要用於恆溫加熱。作者: willing 时间: 2012-5-24 10:12
对于能效测试， 可以参见欧洲Directive2009/125/EC,具体如下。 ! Z/ L' |" a9 @% lTest procedure:+ _ \/ A' \# x' O& m* T( ?
1) Measure the steady standby power consumption (for adaptor without any load) P1= W while the available supply voltage is just 230V after 30 minutes. (Limit: < 0.3W)# l" y! j3 S4 H
2) Connecting the outlet of the adaptor with an adjustable resistor then plugging the AC plug of adaptor into the outlet of digit power meter, adjust the resistor to make sure the output current to be rated current monitoring from a ampere meter /multimeter in series, record the steady power on the power meter PI= W and the DC output voltage Uo= V measuring from a voltmeter/multimeter in parallel while the available supply voltage is just 230V, thus the active efficiency at maximum output level η1=( I x Uo) / PI = ; 9 m2 E0 V8 h3 V6 d+ e9 j
3) Repeat above steps but adjust the resistor to make sure the output current to be0 T1 a% S4 v% l: G3 s) @/ {
75% rated output current, record the steady power PI = W and the DC output voltage Uo= V the active efficiency at middle output levelη2= (I x Uo) / PI = ; * V: t3 X7 U9 m. I2 F6 K+ d4) Repeat above steps but adjust the resistor to make sure the output current to be( `& J' \- t" \: O- [' q0 n
50% rated current, record the steady power PI = W and the DC output voltage Uo= V the active efficiency at middle output level η3= (I x Uo) / PI = ; 1 V4 D4 k2 u3 C8 W! ?/ s# \2 |1 y8 N5 R5) Repeat above steps but adjust the resistor to make sure the output current to be 5 C" T3 v1 }. p25% DC rating current, record the steady power PI= W and the DC output voltage Uo= V the active efficiency at middle output levelη4= (I x Uo) / PI = ;& e, w2 |: n' ~3 H8 F
Average efficiencyη=(η1+η2+η3+η4)/4 = ; ' t6 G- Z0 b- ]/ ]) L+ h作者: 刘阳 时间: 2012-5-24 23:09 ，十分感谢作者: 刘阳 时间: 2012-5-24 23:09
，十分感谢
